3.10.69 \(\int (b x)^{5/2} (\pi +d x)^n (e+f x)^p \, dx\) [969]

Optimal. Leaf size=63 \[ \frac {2 \pi ^n (b x)^{7/2} (e+f x)^p \left (1+\frac {f x}{e}\right )^{-p} F_1\left (\frac {7}{2};-n,-p;\frac {9}{2};-\frac {d x}{\pi },-\frac {f x}{e}\right )}{7 b} \]

[Out]

2/7*Pi^n*(b*x)^(7/2)*(f*x+e)^p*AppellF1(7/2,-n,-p,9/2,-d*x/Pi,-f*x/e)/b/((1+f*x/e)^p)

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Rubi [A]
time = 0.02, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {140, 138} \begin {gather*} \frac {2 \pi ^n (b x)^{7/2} (e+f x)^p \left (\frac {f x}{e}+1\right )^{-p} F_1\left (\frac {7}{2};-n,-p;\frac {9}{2};-\frac {d x}{\pi },-\frac {f x}{e}\right )}{7 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*x)^(5/2)*(Pi + d*x)^n*(e + f*x)^p,x]

[Out]

(2*Pi^n*(b*x)^(7/2)*(e + f*x)^p*AppellF1[7/2, -n, -p, 9/2, -((d*x)/Pi), -((f*x)/e)])/(7*b*(1 + (f*x)/e)^p)

Rule 138

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_Symbol] :> Simp[c^n*e^p*((b*x)^(m +
1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2, (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p},
x] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])

Rule 140

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_Symbol] :> Dist[c^IntPart[n]*((c +
d*x)^FracPart[n]/(1 + d*(x/c))^FracPart[n]), Int[(b*x)^m*(1 + d*(x/c))^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d
, e, f, m, n, p}, x] &&  !IntegerQ[m] &&  !IntegerQ[n] &&  !GtQ[c, 0]

Rubi steps

\begin {align*} \int (b x)^{5/2} (\pi +d x)^n (e+f x)^p \, dx &=\left ((e+f x)^p \left (1+\frac {f x}{e}\right )^{-p}\right ) \int (b x)^{5/2} (\pi +d x)^n \left (1+\frac {f x}{e}\right )^p \, dx\\ &=\frac {2 \pi ^n (b x)^{7/2} (e+f x)^p \left (1+\frac {f x}{e}\right )^{-p} F_1\left (\frac {7}{2};-n,-p;\frac {9}{2};-\frac {d x}{\pi },-\frac {f x}{e}\right )}{7 b}\\ \end {align*}

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Mathematica [A]
time = 0.13, size = 62, normalized size = 0.98 \begin {gather*} \frac {2}{7} \pi ^n x (b x)^{5/2} (e+f x)^p \left (\frac {e+f x}{e}\right )^{-p} F_1\left (\frac {7}{2};-n,-p;\frac {9}{2};-\frac {d x}{\pi },-\frac {f x}{e}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*x)^(5/2)*(Pi + d*x)^n*(e + f*x)^p,x]

[Out]

(2*Pi^n*x*(b*x)^(5/2)*(e + f*x)^p*AppellF1[7/2, -n, -p, 9/2, -((d*x)/Pi), -((f*x)/e)])/(7*((e + f*x)/e)^p)

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Maple [F]
time = 0.02, size = 0, normalized size = 0.00 \[\int \left (b x \right )^{\frac {5}{2}} \left (d x +\pi \right )^{n} \left (f x +e \right )^{p}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x)^(5/2)*(d*x+Pi)^n*(f*x+e)^p,x)

[Out]

int((b*x)^(5/2)*(d*x+Pi)^n*(f*x+e)^p,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="maxima")

[Out]

integrate((b*x)^(5/2)*(pi + d*x)^n*(f*x + e)^p, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="fricas")

[Out]

integral(sqrt(b*x)*(pi + d*x)^n*(f*x + e)^p*b^2*x^2, x)

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)**(5/2)*(d*x+pi)**n*(f*x+e)**p,x)

[Out]

Exception raised: SystemError >> excessive stack use: stack is 3879 deep

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x)^(5/2)*(d*x+pi)^n*(f*x+e)^p,x, algorithm="giac")

[Out]

integrate((b*x)^(5/2)*(pi + d*x)^n*(f*x + e)^p, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int {\left (e+f\,x\right )}^p\,{\left (b\,x\right )}^{5/2}\,{\left (\Pi +d\,x\right )}^n \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e + f*x)^p*(b*x)^(5/2)*(Pi + d*x)^n,x)

[Out]

int((e + f*x)^p*(b*x)^(5/2)*(Pi + d*x)^n, x)

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